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Routing and Switching: Hub, Switch, Router, VLANs and Routing Protocols · রাউটিং ও সুইচিং: হাব, সুইচ, রাউটার, ভিল্যান ও রাউটিং প্রোটোকল

Switching forwards frames inside one network using MAC addresses (layer 2), while routing forwards packets between networks using IP addresses (layer 3). A hub repeats every signal to all ports (one collision domain), a switch learns MAC addresses and gives each port its own collision domain, and a router separates broadcast domains and picks paths from its routing table by longest-prefix match. Routes are static (typed in by an administrator) or dynamic, learned by distance-vector protocols such as RIP (hop count, maximum 15), link-state protocols such as OSPF (cost, Dijkstra's algorithm) or the path-vector protocol BGP between autonomous systems.

সুইচিং ম্যাক অ্যাড্রেস ব্যবহার করে একই নেটওয়ার্কের ভেতরে ফ্রেম পাঠায় (স্তর ২), আর রাউটিং আইপি অ্যাড্রেস ব্যবহার করে এক নেটওয়ার্ক থেকে অন্য নেটওয়ার্কে প্যাকেট পাঠায় (স্তর ৩)। হাব প্রতিটি সিগন্যাল সব পোর্টে পাঠায় (একটি কলিশন ডোমেইন), সুইচ ম্যাক অ্যাড্রেস শিখে প্রতিটি পোর্টকে আলাদা কলিশন ডোমেইন দেয়, আর রাউটার ব্রডকাস্ট ডোমেইন আলাদা করে এবং রাউটিং টেবিল থেকে লংগেস্ট-প্রিফিক্স ম্যাচ দিয়ে পথ বাছাই করে। রুট হয় স্ট্যাটিক (অ্যাডমিনিস্ট্রেটর হাতে লেখেন) অথবা ডায়নামিক, যা শেখা হয় ডিসট্যান্স-ভেক্টর প্রোটোকল যেমন আরআইপি (হপ কাউন্ট, সর্বোচ্চ ১৫), লিংক-স্টেট প্রোটোকল যেমন ওএসপিএফ (কস্ট, ডাইক্সট্রার অ্যালগরিদম) অথবা অটোনোমাস সিস্টেমগুলোর মধ্যে পাথ-ভেক্টর প্রোটোকল বিজিপি দিয়ে।

Asked in past exams
65
Papers
44

1. The devices: repeater, hub, bridge, switch, router, gateway

Each interconnecting device works at a particular OSI layer, and that layer decides what it can "see" (the layers are explained on the OSI and TCP/IP models page).

Device Layer Forwards using What it does Collision domains Broadcast domains
Repeater 1 (Physical) Nothing (just signals) Regenerates a weakened signal to extend a cable's reach Does not split Does not split
Hub 1 Nothing A multiport repeater: copies every bit out of every other port 1 for the whole hub 1
Bridge 2 (Data Link) MAC address Joins two (or a few) segments and filters frames between them; the segments still look like one network to higher layers 1 per port 1
Switch 2 MAC address A multiport bridge with hardware forwarding; sends each frame only to the port where the destination is 1 per port 1 (unless VLANs are used)
Router 3 (Network) IP address Joins different networks and chooses the path for each packet 1 per interface 1 per interface
Gateway Up to 7 Depends on the protocols Connects networks that use different protocols and translates between them – –

Points that exams like:

  • A switch has memory: it stores a MAC address table and buffers frames. "A switch has no memory" is the wrong statement in MCQs.
  • A managed switch can be configured port by port, for example to create VLANs; an unmanaged switch cannot.
  • A layer-3 switch is a switch that can also route between VLANs.
  • Default gateway has a narrower meaning: the router a host sends packets to when the destination is outside its own subnet. In everyday use "gateway" and "router" overlap, but a true gateway also converts between protocols (for example email or VoIP gateways).
  • A firewall filters traffic by security rules; a gateway connects and translates. A modem converts digital data to signals for a telephone, cable or fibre line, while a router chooses paths between IP networks (home "routers" usually combine a modem, router, switch and Wi-Fi access point in one box).

2. Collision domains and broadcast domains

  • A collision domain is the set of devices whose transmissions can collide because they share one medium (half duplex). Only one device in it can send at a time.
  • A broadcast domain is the set of devices that receive each other's broadcast frames (such as ARP requests or DHCP Discover).

Rule: hubs split nothing, switches and bridges split collision domains, routers split collision domains and broadcast domains. Each switch port is its own collision domain, so a 12-port switch gives 12 collision domains but only 1 broadcast domain.

Worked example 1: counting domains. A router has three interfaces:

  • interface 1 connects to a 24-port switch; 8 of its ports are in use: one uplink to the router, six PCs, and one hub that has 4 PCs on it;
  • interface 2 connects to a hub with 5 PCs;
  • interface 3 is a serial link to an ISP router.
A router with three interfaces connects a switch (with six PCs and a hub of four PCs), a hub of five PCs, and a serial WAN link.
  1. Broadcast domains: count router interfaces: 3.
  2. Collision domains on the switch: every used switch port is one: the uplink to the router (1), six PCs (6), and the hub port (1, which includes the hub and all 4 of its PCs, because a hub does not split collisions). That is 8.
  3. Interface 2: the hub, its 5 PCs and the router interface share one collision domain: 1.
  4. Interface 3: the serial link is 1.
  5. Total collision domains = 8 + 1 + 1 = 10.

The shortcut for the simple MCQ form: N switch ports → N collision domains, 1 broadcast domain; N hub ports → 1 and 1; N router interfaces → N and N.

3. How a switch works

A switch keeps a MAC address table (often called the CAM table) mapping MAC addresses to ports, and builds it by itself:

  1. Learn: for every incoming frame it records source MAC → incoming port.
  2. Forward or filter: if the destination MAC is in the table, it sends the frame only out of that port (and drops it if that port is the one it came in on).
  3. Flood: if the destination is unknown, or is the broadcast address FF-FF-FF-FF-FF-FF, it sends the frame out of every port except the incoming one.
  4. Age: entries not seen for a while (commonly 300 seconds) are removed, so the table follows devices that move.

Worked example 2: the table filling up. PCs A, B and C are on ports 1, 2 and 3 of a new switch with an empty table.

Frame Switch learns Destination known? Action
A → B A is on port 1 No Flood to ports 2 and 3
B → A B is on port 2 Yes (port 1) Forward only to port 1
C → broadcast C is on port 3 Broadcast Flood to ports 1 and 2
A → C (A already known) Yes (port 3) Forward only to port 3

Switching methods.

Method Starts forwarding after Error checking Delay
Store-and-forward The whole frame is received and its CRC (FCS) checked Drops damaged frames Highest: a 1,518-byte frame at 100 Mbps adds 121.44 µs
Cut-through The destination MAC address (first 6 bytes) is read None: bad frames are passed on Lowest
Fragment-free The first 64 bytes are received (where collisions show up) Catches collision fragments only In between

MAC flooding is an attack in which a host sends thousands of frames with fake source MACs until the table is full; the switch then floods unknown frames like a hub and the attacker can capture other people's traffic. It is prevented with port security (limit the number of MAC addresses per port and shut down or block violators), 802.1X port authentication, and by disabling unused ports.

4. VLANs and Spanning Tree

A VLAN (virtual LAN) divides one physical switch network into several logical networks, each its own broadcast domain. Departments such as Accounts and HR can share switches yet stay separated, which cuts broadcast traffic, improves security and makes moves and changes easier. VLANs reduce management complexity, so "VLANs increase network management complexity" is the false statement in MCQs. VLANs are created on switches, and traffic between VLANs must pass through a router or layer-3 switch.

  • IEEE 802.1Q adds a 4-byte tag to Ethernet frames on trunk links (links carrying many VLANs); its 12-bit VLAN ID gives 4,096 values, of which 1 – 4,094 are usable (0 and 4,095 are reserved). An access port belongs to one VLAN and sends untagged frames.
  • Static (port-based) VLAN: the administrator assigns each port to a VLAN; simple and the most common. Dynamic VLAN: a device is placed in a VLAN automatically by its MAC address or login, using a policy server, so it keeps its VLAN wherever it plugs in.

Spanning Tree Protocol (STP, IEEE 802.1D, now part of 802.1Q). Redundant links between switches create loops, and since Ethernet frames have no TTL, a broadcast would circle forever (a broadcast storm) and MAC tables would keep changing. STP prevents this:

  1. The switches elect a root bridge: the one with the lowest bridge ID (priority, default 32,768, then MAC address).
  2. Every other switch picks its root port, the port with the lowest path cost to the root.
  3. Each segment gets one designated port; all remaining ports are put into blocking state, leaving a loop-free tree.
  4. If an active link fails, a blocked port moves through listening and learning to forwarding. With the default timers (hello 2 s, max age 20 s, forward delay 15 s) this takes 30 to 50 seconds; Rapid STP (802.1w) usually converges in a few seconds.

5. Routing: the routing table and longest-prefix match

A router reads a packet's destination IP address, looks it up in its routing table, and sends the packet to the next hop through an outgoing interface. It also decrements the TTL and builds a new layer-2 frame, so the IP addresses stay the same end to end (unless NAT rewrites them) while the MAC addresses change at every hop; a MAC address never leaves the local network. To build that frame the router needs the next hop's MAC address, which it finds with ARP (and keeps in its ARP cache), just as a host does for its default gateway.

Each routing table entry holds a destination network and prefix, a next hop or exit interface, and a metric. When several entries match, the router uses the most specific one: the entry with the longest prefix (longest-prefix match). The default route 0.0.0.0/0 matches every address with a prefix length of 0, so it is used only when nothing else matches (the "gateway of last resort"). The address arithmetic is explained on the IP addressing and subnetting page.

Worked example 3: longest-prefix match.

Destination Next hop
10.0.0.0/8 A
10.1.0.0/16 B
10.1.4.0/22 C
10.1.5.128/25 D
0.0.0.0/0 E
  1. 10.1.5.200: /8 matches (10.x.x.x), /16 matches (10.1.x.x), /22 matches (10.1.4.0 – 10.1.7.255), /25 matches (10.1.5.128 – 10.1.5.255), and /0 always matches. The longest is /25 → D.
  2. 10.1.5.20: inside 10.1.4.0/22 but below .128, so not in the /25 → C.
  3. 10.1.6.9: the /22 covers 10.1.4.0 – 10.1.7.255 → C.
  4. 10.2.3.4: only /8 and /0 match → A.
  5. 11.0.0.1: only the default route matches → E.
For each packet the router finds every table entry that contains the destination, keeps the longest prefix, and falls back to the default route or drops the packet.

6. Static vs dynamic routing

Point Static routing Dynamic routing
How routes appear Typed in by an administrator Learned from other routers by a routing protocol
Reacts to failures No, until someone edits it Yes, automatically
Bandwidth and CPU use None (no updates sent) Uses some for updates and calculations
Security Higher (nothing advertised) Lower unless updates are authenticated
Best for Small or stub networks, default routes to an ISP Medium and large networks with redundant paths

A typical static default route on a Cisco router toward an ISP: ip route 0.0.0.0 0.0.0.0 203.0.113.1 (destination, mask, next hop). "Which routing does not consume network bandwidth?" is keyed static routing. Routing in which each router decides by itself on the fly, as in mobile ad hoc networks with no fixed infrastructure, uses on-demand protocols such as AODV that find routes only when needed, saving bandwidth and battery.

7. Distance vector, link state and path vector

An autonomous system (AS) is a group of networks and routers under one administration (an ISP, a large organisation). Interior gateway protocols (IGPs) route inside an AS (intra-domain): RIP, OSPF, IS-IS, EIGRP. Exterior gateway protocols route between ASes (inter-domain): BGP.

Point Distance vector (RIP) Link state (OSPF) Path vector (BGP)
What a router knows Only distances its neighbours report ("routing by rumour") A full map of the area Full AS paths to each network
What it sends Its whole table to its neighbours, periodically (RIP: every 30 s) Link-state advertisements flooded to all routers in the area when something changes (and refreshed every 30 minutes) Updates to its peers over TCP 179
Algorithm Bellman-Ford Dijkstra's shortest path first (SPF) Best-path selection by policy and AS-path
Metric Hop count (maximum 15; 16 = unreachable) Cost, based on bandwidth Path attributes (AS-path length, policies)
Convergence Slow; can count to infinity Fast Slow, but stable at Internet scale
Scope Small networks (IGP) Large networks with areas; area 0 is the backbone (IGP) Between autonomous systems: the Internet (EGP)

Cisco's EIGRP is an advanced distance-vector protocol (sometimes called "hybrid") using the DUAL algorithm; IS-IS is another link-state IGP.

Distance vector loops and their fixes. When a link fails, neighbours can keep advertising the dead route to each other, increasing it step by step (count to infinity). Fixes: a maximum hop count (RIP's 16 = infinity), split horizon (do not advertise a route back out of the interface it was learned on), route poisoning (advertise a failed route with an infinite metric, 16 in RIP), poison reverse (advertise it back with infinity), and hold-down timers.

RIPv1 vs RIPv2. RIPv1 is classful (its updates carry no subnet mask) and broadcasts them; RIPv2 is classless (it carries the mask, so it supports VLSM, and adds authentication) and multicasts its updates to 224.0.0.9. OSPF details: OSPF runs directly over IP (protocol number 89), sends Hello packets to 224.0.0.5 to find and keep neighbours, and on a multi-access network such as Ethernet elects a designated router (DR) and a backup (BDR), reached at 224.0.0.6, so that every router exchanges LSAs with the DR instead of with every other router.

Worked example 4: a distance-vector update. Router A has links to B (cost 2) and C (cost 5). B reports: C at 1, D at 3. C reports: B at 1, D at 1. A takes, for each destination, the minimum of link cost + neighbour's distance:

  • to D: via B = 2 + 3 = 5, via C = 5 + 1 = 6 → 5 via B;
  • to C: via B = 2 + 1 = 3, direct = 5 → 3 via B (the direct link is not the best path);
  • to B: direct 2, via C = 5 + 1 = 6 → 2 direct.

Worked example 5: Dijkstra (as OSPF uses it). Links and costs: A–B 4, A–C 2, B–C 1, B–D 5, C–D 8, C–E 10, D–E 2. From A:

  1. Start: A = 0; all others unknown (∞).
  2. Fix A. Neighbours: C = 2, B = 4.
  3. Fix the smallest, C (2). Through C: B = 2 + 1 = 3 (better than 4), D = 2 + 8 = 10, E = 2 + 10 = 12.
  4. Fix B (3). Through B: D = 3 + 5 = 8 (better than 10).
  5. Fix D (8). Through D: E = 8 + 2 = 10 (better than 12).
  6. Fix E (10). Done.

Shortest paths: C = 2 (A-C), B = 3 (A-C-B), D = 8 (A-C-B-D), E = 10 (A-C-B-D-E).

OSPF cost. OSPF's metric is cost. On Cisco routers cost = 10⁸ ÷ interface bandwidth in bps (rounded down, minimum 1): 10 Mbps → 10, a 1.544 Mbps T1 → 64, 100 Mbps and faster → 1 (which is why faster links need a larger reference bandwidth).

8. Administrative distance and tricky exam cases

When two different sources (say OSPF and RIP) offer a route to the same network, the router trusts the one with the lower administrative distance (AD). AD values are Cisco defaults, not an Internet standard:

Route source Default AD
Directly connected 0
Static route 1
External BGP 20
Internal EIGRP 90
OSPF 110
IS-IS 115
RIP 120
External EIGRP 170
Internal BGP 200
Unknown (never used) 255

Order of decisions: longest prefix first, then lowest AD between protocols, then lowest metric within one protocol. A /24 learned by RIP beats a /16 learned by OSPF, because prefix length is compared before AD.

  • Hub bandwidth. Ten users on a 10 Mbps half-duplex hub share 10 Mbps, so each gets about 10 ÷ 10 = 1 Mbps. On a switch, each port would get the full 10 Mbps.
  • "How many pairs of stations can communicate at once on an Ethernet LAN?" Keyed 1: classic shared Ethernet (a bus or hub) is one collision domain. With a full-duplex switch, many pairs can talk at once; read the question.
  • "When a host on network A sends to network B, which address does the router look at?" The destination IP address. A MAC address stays on the local LAN.
  • Pairs of routing protocols. Intra-domain: RIP and OSPF. Routing protocols in general: RIP, OSPF, EIGRP, BGP. Routed protocol: IP. BGP uses the AS-path to build its table. RIP uses Bellman-Ford; OSPF uses Dijkstra.
  • Ethernet is IEEE 802.3; Wi-Fi is 802.11; VLAN tagging is 802.1Q.

Practice · অনুশীলন

  1. How many collision domains and broadcast domains does a 16-port switch create (no VLANs)? What if it were a 16-port hub?
    Answer

    Switch: 16 collision domains (one per port) and 1 broadcast domain. Hub: 1 collision domain and 1 broadcast domain.

  2. A routing table has 172.16.0.0/16 → R1, 172.16.32.0/19 → R2 and 0.0.0.0/0 → R3. Where do packets for 172.16.45.9 and 172.17.1.1 go?
    Answer

    172.16.45.9: the /19 covers 172.16.32.0 – 172.16.63.255, so it matches both the /16 and the /19; the longer /19 wins → R2. 172.17.1.1 matches only the default route → R3.

  3. What is the maximum hop count in RIP, and what does a hop count of 16 mean?
    Answer

    15 hops is the maximum reachable distance; 16 means infinity, that is, the network is unreachable. This limit stops count-to-infinity loops and restricts RIP to small networks.

  4. Compare distance-vector and link-state routing in three points.
    Answer

    Distance vector: routers send their whole table to neighbours periodically, know only neighbour-reported distances, use Bellman-Ford and converge slowly (RIP). Link state: routers flood link-state advertisements to all routers when links change, each builds a full map, uses Dijkstra and converges fast (OSPF).

  5. Why are VLANs used, and what device is needed for two VLANs to communicate?
    Answer

    VLANs split one switched network into separate broadcast domains, reducing broadcast traffic, improving security and letting users be grouped logically regardless of location. Traffic between VLANs needs a router or a layer-3 switch (inter-VLAN routing).

Asked in past exams · আগের পরীক্ষায় যেভাবে এসেছে

Our past papers have 65 questions on this topic (33 MCQ, 32 written) from 44 exams. Here are 12 of them; each links to its full paper.

  1. How many collision domians are created when you segment a network with a 12-port switch?

    Model answer on the paper page

  2. What is Routing? Explain different types of Routing? Why using benefit of an Adhoce routing? Which routing algorithm is used in shortest path algorithm?

    Model answer on the paper page

  3. What is route poisoning?

    • a)It sends back the protocol received from a router as a poison pill, which stops the regular updates.
    • b)It is information received from a router that can't be sent back to the originating router.
    • c)It prevents regular update messages from reinstalling a route that has just come up.
    • d)It describes when a router sets the metric for a downed link to infinity. (correct answer)
    Explanation · ব্যাখ্যা

    Correct answer: (d) It describes when a router sets the metric for a downed link to infinity.

    Route poisoning means that when a router learns a route has failed, it does not silently drop it. Instead it sets that route's metric to the protocol's "infinity" value, which is 16 in RIP, and advertises it, usually at once in a triggered update. Neighbours then mark the destination as unreachable straight away instead of waiting for their own timers. RIP keeps advertising the poisoned route with metric 16 until its garbage-collection timer (120 s) removes it, which helps stop routing loops and count-to-infinity.

    Why the other options are wrong

    • (a) It sends back the protocol received from a router as a poison pill, which stops the regular updates.: No such mechanism exists; poisoning changes a route's metric and does not stop regular updates.
    • (b) It is information received from a router that can't be sent back to the originating router.: That is the split horizon rule.
    • (c) It prevents regular update messages from reinstalling a route that has just come up.: This is a garbled description of the hold-down timer, which blocks a route that has just gone down, not one that has come up.

    Tip: Split horizon = don't send it back; poisoned reverse = send it back with ∞; route poisoning = advertise a failed route with ∞; hold-down = ignore news about a failed route for a while.

    Sources: RFC 2453: RIP Version 2; An Introduction to IGRP - Cisco

  4. Write short note: Node, Backbone, Router and Gateway.

    Model answer on the paper page

  5. Which information is wrong for a switch?

    • a)Stores MAC address table
    • b)Operates at Data Link Layer
    • c)Forwards the packet to the intended computer
    • d)Has no memory (correct answer)
    Explanation · ব্যাখ্যা

    Correct answer: (d) Has no memory

    The question asks which statement is WRONG about a switch. A switch certainly has memory: it learns which MAC address sits behind which port and keeps that list in its MAC address table, held in CAM (content-addressable memory). Ports also buffer frames in memory before forwarding them. So "has no memory" is false.

    Why the other options are wrong (they are true statements)

    • (a) Stores MAC address table: True; the switch builds this table by reading the source MAC address of every incoming frame.
    • (b) Operates at Data Link Layer: True; a basic switch is a Layer 2 device.
    • (c) Forwards the packet to the intended computer: True; it sends a frame only out of the port linked to the destination MAC address. (Strictly, at Layer 2 the unit is a frame, not a packet.)

    Tip: Hub = no table, repeats everything; switch = MAC table in memory, forwards selectively.

    Source: Troubleshoot LAN Switching Environments - Cisco

  6. (a) What are the difference among Hub, Switch and Routers?

    Model answer on the paper page

  7. Describe about Hub, Switch and Router.

    Model answer on the paper page

  8. Which of the following is the metric used for OSPF?

    • a)Latency
    • b)Cost (correct answer)
    • c)Bandwidth
    • d)Next hop
    Explanation · ব্যাখ্যা

    Correct answer: (b) Cost

    OSPF describes every route with one dimensionless number called cost. Each router interface is given a cost (the lower the cost, the more attractive the link), and the cost of a path is the sum of the outgoing-interface costs along it. Every router runs the SPF (Dijkstra) calculation on its link-state database and installs the path with the lowest total cost. Many implementations set the default interface cost from the link bandwidth (faster link → smaller cost), but the value OSPF actually compares is the cost.

    Why the other options are wrong

    • (a) Latency: OSPF does not measure delay; latency is not part of its metric.
    • (c) Bandwidth: Bandwidth can be used to calculate a default cost, but OSPF compares costs, not bandwidth figures, and an administrator can set any cost regardless of bandwidth.
    • (d) Next hop: The next hop is the result of the route calculation (the neighbour a packet is sent to), not a metric for comparing paths.

    Tip: RIP → hop count; OSPF → cost; EIGRP → composite (bandwidth + delay); BGP → path attributes such as AS_PATH.

    Source: RFC 2328: OSPF Version 2; Introduction to OSPF (Juniper Networks, Junos OS documentation)

  9. Which one is false with respect to a VLAN?

  10. IEEE ____ Standard used Ethernet LAN?

  11. What is the primary function of a Repeater in a computer network?

  12. কম্পিউটার নেটওয়ার্ক কী? হাব, সুইচ, রাউটার ও রিপিটার সম্পর্কে চিত্রসহ বর্ণনা লিখুন।

Common mistakes · সাধারণ ভুল

  • Saying a switch splits broadcast domains: it splits collision domains only; routers (and VLANs) split broadcast domains.
  • Counting a hub attached to a switch port as several collision domains: the hub and all its devices form one.
  • Picking the first matching routing entry instead of the longest prefix, or comparing administrative distance before prefix length.
  • Writing that OSPF uses hop count or Bellman-Ford: it uses cost and Dijkstra; RIP uses hop count and Bellman-Ford.
  • Thinking a router forwards by MAC address: it forwards by destination IP; the MAC addresses are rewritten at every hop.
  • Calling BGP an interior protocol: it is the exterior (inter-AS), path-vector protocol of the Internet.

বাংলায় সংক্ষেপে

  • হাব ও রিপিটার স্তর ১-এ, ব্রিজ ও সুইচ স্তর ২-এ (ম্যাক অ্যাড্রেস), রাউটার স্তর ৩-এ (আইপি অ্যাড্রেস) কাজ করে।
  • সুইচের প্রতিটি পোর্ট আলাদা কলিশন ডোমেইন; রাউটারের প্রতিটি ইন্টারফেস আলাদা ব্রডকাস্ট ডোমেইন। ১২ পোর্টের সুইচে ১২টি কলিশন ডোমেইন।
  • সুইচ উৎস ম্যাক অ্যাড্রেস দেখে ম্যাক টেবিল শেখে; অজানা গন্তব্যের ফ্রেম সব পোর্টে ফ্লাড করে।
  • ভিল্যান একটি সুইচকে একাধিক ব্রডকাস্ট ডোমেইনে ভাগ করে (IEEE 802.1Q); এসটিপি লুপ ঠেকাতে কিছু পোর্ট ব্লক করে।
  • রাউটার লংগেস্ট-প্রিফিক্স ম্যাচ দিয়ে রুট বাছে; ০.০.০.০/০ হলো ডিফল্ট রুট।
  • আরআইপি ডিসট্যান্স-ভেক্টর (বেলম্যান-ফোর্ড, সর্বোচ্চ ১৫ হপ); ওএসপিএফ লিংক-স্টেট (ডাইক্সট্রা, মেট্রিক কস্ট); বিজিপি পাথ-ভেক্টর, অটোনোমাস সিস্টেমগুলোর মধ্যে চলে।
  • স্ট্যাটিক রাউটিং হাতে কনফিগার করা হয় ও ব্যান্ডউইথ খরচ করে না; ডায়নামিক রাউটিং নিজে থেকেই পরিবর্তনের সঙ্গে খাপ খায়।

Updated 2026-10-18. Written by ARBS Academy; the past exam questions are from public recruitment exams.